What is the minimum score in IIT Mains to get to IIIT Bhubaneswar?

Answer
Share
More
2 Answers

SS
Sunita Saha Posted On - Jun 22, 2023
M.Tech from IIT Bhubaneswar (2020)

International Institute of Information Technology (IIIT) Bhubaneswar is a renowned university, situated in Orissa. It is well known for its flagship program, B.Tech CSE, which is offered for a 4-year duration and is a complete residential program. The four other specializations in B.Tech offered by IIIT Bhubaneswar are- Electrical and Electronics Engineering, Electronics and Telecommunication Engineering, Information Technology, and Computer Engineering.

Admission into IIIT Bhubaneswar B.Tech program is based on the JEE Mains rank followed by JoSAA counseling.

Here is the IIIT Bhubaneswar course-wise JEE Main Cut off for the year 2022 (general category):

Course Name

Cut-off by Rank

(Round 1)

Cut-off by Rank

(Round 2)

B.Tech Computer Science and Engineering

20543

23192

B.Tech Computer Engineering

23832

26248

B.Tech IT

23896

26369

B.Tech Electrical and Electronics 

34445

36217

B.Tech Electronics and Telecommunication

31587

34371

You can also check the course-wise cut-offs for other categories for the past 4 years to reach a better conclusion. 

You can analyze the previous years' trends to figure out the JEE Mains cut-offs for different courses at IIIT Bhubaneswar.

0
0
Share
Comments

Comments



No Comments To Show
AM
Abhinav Mundra Posted On - Aug 14, 2020
B.Tech from International Institute of Information Technology, Bhubaneswar (2021)

Students can choose any branch of their choice, if they belong from Odisha, also if they have secured 100+ marks in their IIT Mains. Approximately 50% of seats are reserved only for Odisha Students. Candidates from other states will not be applicable to any type of Quota. IIIT Bhubaneswar conducts its own Counselling process for the Admission of Odisha Students.

The admission of Odisha Candidates is done on the basis of the JEE Main 2020 CRL ranking but for Non- Odisha Candidates it is done on the basis of JoSSA/CSAB 2020. Candidates from outside of Odisha required to score between 120 - 125 for the CSE branch and 90 marks for the IT branch in the Year 2017. However, if you can cross these criteria then you will surely get any branch of your choice for 2020. You must have to score little above the qualification level for JEE advanced. It would be a safe line for students. The chances are low if your score is less than 125. You may or may not get the chance to ensure the seat.

The cut off criteria completely depends on the demand of the engineers in India. It also depends on the Category of a Candidate. If we talk about General Category students, one must secure a minimum of 130 marks for CSE, 120 marks for ECE, and 110 marks for EEE in their JEE Mains. Admission into CSE is a little bit difficult to predict the admission rate for General Candidates. For this, students should score above the cut off marks. Also, the Government gives the advantage to female students of Odisha by reserving 95% seats.

Do not panic and keep trying your best. You will achieve your goal successfully.

0
0
Share
Comments

Comments



No Comments To Show