AIIMS MBBS 2019 Question Paper with Answer Key PDF (May 26 - Afternoon Session)

AIIMS MBBS Questions

• 1.

  Elemental silicon to be used as a semiconductor is purified by

  • heating under vacuum
  • floatation
  • zone refining
  • electrolysis
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• 2.

  The primary winding of a transformer has 500 turns whereas its secondary has 5000 turns. The primary is connected to an A.C. supply 20 V, 50 Hz. The secondary will have an output of

  • 2 V, 50 Hz
  • 2 V, 5 Hz
  • 200 V, 50 Hz
  • 200 V, 500 Hz.
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• 3.

  The following equilibria are given : $N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}\, K _{1}$ $N2 + O2 \rightleftharpoons 2NO\, K_2$ $H_2 + \frac{1}{2} O_2 \rightleftharpoons H_2 O \, K_3$ The equilibrium constant of the reaction $2NH_3 + \frac{5}{2} O_2 \rightleftharpoons 2NO + 3H_2 O$ in terms of $K_1,\, K_2$ and $K_3$ is

  • $K_1 K_1 K_3$
  • $\frac{K_1 K_2}{K_3}$
  • $\frac{K_1 K_3^2}{K_2}$
  • $\frac{K_2 K_3^3}{K_1}$
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• 4.

  The following equilibria are given : $N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}\, K _{1}$ $N2 + O2 \rightleftharpoons 2NO\, K_2$ $H_2 + \frac{1}{2} O_2 \rightleftharpoons H_2 O \, K_3$ The equilibrium constant of the reaction $2NH_3 + \frac{5}{2} O_2 \rightleftharpoons 2NO + 3H_2 O$ in terms of $K_1,\, K_2$ and $K_3$ is

  • $K_1 K_1 K_3$
  • $\frac{K_1 K_2}{K_3}$
  • $\frac{K_1 K_3^2}{K_2}$
  • $\frac{K_2 K_3^3}{K_1}$
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• 5.

  The neutralization of \(NaOH\) by \(H _{2} SO _{4}\) takes place as follows \(H _{2} SO _{4}+2 NaOH \longrightarrow Na _{2} SO _{4}+ H _{2} O\) 

  For complete neutralization Equivalents of acid = equivalents of base Equivalents of \(NaOH =\) moles \(\times\) acidity \(=1 \times 1=1\) Equivalents of \(H _{2} SO _{4}=\frac{x}{98} \times 2=\frac{x}{49}\) (Mol. mass of \(H _{2} SO _{4}=98\) ) Putting the values \(1 \times 1 =\frac{x}{49}\) \(\Rightarrow x =49\, g\) but \(H _{2} SO _{4}\) is \(70 \%\) let \(y g 70 \% H _{2} SO _{4}\) is required \(\frac{70}{100} \times y =49\) \(\Rightarrow y =70\, g\)

  • 10 min
  • 12 min
  • 20 min
  • 15 min
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• 6.

  A certain compound X when treated with copper sulphate solution yields a brown precipitate. On adding hypo solution, the precipitate turns white. The compoundXis

  • $K_2CO_3$
  • KI
  • KBr
  • $K_3PO_4$
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