Question: A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, What will be the time at the end of 10 days?
- 11:54:40 AM
- 11:56:24 AM
- 12:16:40 PM
- 11:54:24 AM
- 12:06:36 PM
“A Clock loses a Minute Every Three Hours for 4 Days and Gains 1% in the Subsequent 6 Days.”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "501 GMAT Questions". To solve GMAT Problem Solving questions a student must have knowledge about a good number of qualitative skills. GMAT Quant section consists of 31 questions in total. The GMAT quant topics in the problem-solving part require calculative mathematical problems that should be solved with proper mathematical knowledge.
Solution and Explanation
Approach Solution 1:
It is given in the question that a clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM it is asked to find out the time at the end of 10 days.
It is given that the Clock loses 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.
Also, it is given that the clock gains 1% in the subsequent 6 days = 1% in 6*24*60 minutes in 6 days = 86.40 minutes in 6 days.
The net gain in 10 days = total gain in 10 days - total loss in 10 days
11AM + 54.4 minutes = 11:54 and 4/10th of a minute or 24 seconds.
Therefore the correct answer is option D.
Approach Solution 2:
It is given in the question that a clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days.
Loses 8 minutes each day.
so total loss = 4×8 = 32 min
subsequent 6 days = 6×24×60 minutes
1% gain = ( 6×24×60)/100 = 86.4 minutes
so, total gain = 86.4 - 32 = 54.4 min = 54 + 0.4 min = 54 minutes + 0.4 × 60 seconds = 54min + 24seconds
10 days later the clock should be 54 min and 24 seconds fast.
so time, 11:54:24 am (Answer D)
Approach Solution 3:
As per the problem statement, clock loses 8 minutes each day.
Hence, total loss = 4×8 = 32min
subsequent 6 days = 6×24×60 minutes
1% gain = ( 6×24×60)/100 = 86.4 minutes
Hence, total gain
= 86.4 - 32
= 54.4 min
= 54 + 0.4 min
= 54 minutes + 0.4 × 60 seconds
= 54min + 24seconds
We know that:
10 days later the clock should be 54 min and 24seconds fast.
so time would be
11:54:24 am
Hence, D is the correct answer.
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