
bySayantani Barman Experta en el extranjero
Question: A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45, there are 3 stones lift in each case. How many stones atleast can there be in the heap?
- 2403
- 3603
- 4803
- 6203
- 7203
“A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45, there are 3 stones lift in each case. How many stones atleast can there be in the heap?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book “GMAT Official Guide Quantitative Review”.
To solve GMAT Problem Solving questions a student must have knowledge about a good amount of qualitative skills. The GMAT Quant topic in the problem-solving part requires calculative mathematical problems that should be solved with proper mathematical knowledge.
Answer:
Approach Solution 1:
A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45, there are 3 stones left in each case. How many stones at least can there be in the heap?
The number of stones are in the form of = LCM (16, 20, 25, and 45) * k + 3 = 3600 * k + 3
Since the heap of stones can be made up of the groups of 21, the number of stones 3600 * k + 3 should be divisible by 21
Since the remainder when 3 divided by 21 is 3. 3600 * k should leave a remainder 18 when divided by 21
Remainder when 3600 divided by 21 = 9
9*k = 18
k = 2
Number of stones = 3600 * 2 + 3 = 7203
Correct option: E
Approach Solution 2:
Heap of stones can be made up into groups of 21, which means that the total number of stones in that heap must be divisible by 21 = 7 * 3
But it should not be divisible by 16 (4*4), 20 (4*5), 25 (5*5) and 45 (9*5)
Vertically scan through the options. Only option (e) is divisible by 7.
Correct option: E
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