Question: What is the value of │x + 7│?
(1) │x + 3│= 14
(2) (x + 2)^2 = 169
- 12
- 10
- 11
- 14
Solution and Explanation:
Approach Solution 1:
The solution can be achieved with two different approaches. First assuming |x+3| = 14. This assumption will give two probable outcomes; x+3 = 14 and x+3 = -14.
This implies x = 11, -17.
The mentioned value is not sufficient for the values mentioned above. Thus, this can’t be the solution.
The second approach is (x+2)^2 = 169. Thus, this implies x+2 = +-13. Therefore, the probable values of x are -15, and 11.
Now, comparing both the assumptions, there is a single value of x that satisfies both the cases i.e x=11. Therefore, the answer will be x=11.
Approach Solution 2:
Another approach that can be adapted by candidate are following these three steps:
- Apply the rule that says: If |x| = k, then x = k and/or x = -k
- Solve the resulting equations
- Plug in the solutions to check for extraneous roots
So for the above mentioned question, x+3 = 14 Or x+3 = -14. Upon evaluation, we get two values of x, 11 and -17.
The next approach is to input the value of x within the given equations in the question. Thus, we get;
If x = 11, then |x + 7| = |11 + 7| = 18
If x = -17, then |x + 7| = |-17 + 7| = 10
Since, it doesn’t satisfy the value in the question, thus, this value is not sufficient.
Now, using the second equation mentioned in the question, (x+2)² = 169 implies (x+2) = 13 OR (x+2) = -13. Upon solving the equation, we get x = 11 OR x = -15. Now putting the value of x in the given equation |x + 7|, we get;
if x = 11, then |x + 7| = |11 + 7| = 18
if x = -15, then |x + 7| = |-15 + 7| = 8
Combining both the equations, |x + 7| = 18 OR 10 and |x + 7| = 18 OR 8, derives the conclusion that |x + 7| must equal 18. Thus, upon solving |x + 7| = 18, the value x= 11. Therefore, the value of x=11.
Approach Solution 3:
Statement 1
In order to solve this, we need to consider two different cases.
Case 1: x + 3 > 0
Thus, if x + 3 > 0 then the value of |x+3| will be positive. This implies x+3 = 14, thus, x= 14-13
Further, x=11.
Now putting the value of x=11 in x+3=14 we get 11+3=14, that justifies the case 14 > 0.
Case 2: Consider x+3 < 0
Thus, this implies that the value of |x+3| will be negative.
Therefore, the equation formed will be -(x+3) = 14,
=> x= -14-3
=> x= -17.
Now putting the value of x=-17 in x+3=14 we get -17+3=14, that justifies the case -14 < 0.
Two different values => x alone is not sufficient
Statement 2
The second statement in the question states that (x + 2)^2 = 169
Since, \(\sqrt{(x^2)}=|x|\), thus it can be stated that |x+2|=13.
Case 1: x+2>0
It can be concluded from statement 1 that value of |x+2| will be positive and hence it will be x+2=13 => x=11.
Putting the value of x in |x+2|=13, |11+2|=13, thus, it is justified that x=11.
Case 2: x+2<0
As mentioned in statement 1, it can be stated that the value of |x+2| will be negative and hence it will be -(x+2)
Implies; -x-2=13
Therefore, x=-15
Putting the value of x in -|x+2|=13, -15+2=-13, thus, it is justified that x=-15 is justified.
Combining both the statements, we get a common value x=11, thus, the answer will be 11.
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