The Smallest 3-Digit Positive Integer Obtained By Adding Two Positive Two-Digit Numbers GMAT Problem Solving

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Question:The smallest 3 digit positive integer obtained by adding two positive two-digit numbers, one of which has the units and tens places interchanged as the other is ___

  1. 100
  2. 101
  3. 105
  4. 110
  5. 121

‘The smallest 3-digit positive integer obtained by adding two positive two-digit numbers' - is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book “The Official Guide for GMAT Reviews”. To solve GMAT Problem Solving questions a student must have knowledge about a good amount of qualitative skills. The GMAT Quant topic in the problem-solving part requires calculative mathematical problems that should be solved with proper mathematical knowledge.

Solution and Explanation:

Approach Solution 1:

This question can be solved by only one approach.
It is asked in the question to find out the smallest three-digit positive integer which can be obtained by adding two positive two-digit numbers, one which has the units and tens place interchanged with one another.
To understand this clearly
Let us take an example,
If a number is 34 then the other number had to be 43
Note that in both the numbers the digits in ones and tens place are replaced.
To solve this question let us assume that the number is ab
Where b is the one’s digit and a is the tens digit.
The number can be written as 10a + b
If this is the first number then the second number can be written as ba
This number can be written as 10b + a
This sum is required to be the minimum 3-digit number.
Taking sum of these numbers = 10a + b + 10b + a
= 11a + 11b
= 11 (a + b)
It can be clearly seen that the three digits number is divisible by 11.
The smallest three-digit number divisible by 11 is 110 and 121, but 110 is the smallest number therefore this is the correct answer.
The correct option will be option D.

Correct Answer: D

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