bySayantani Barman Experta en el extranjero
Question: Two marbles are drawn from a jar with 10 marbles. If all marbles are either red or blue, is the probability that both marbles selected will be red greater than \(\frac{3}{5}\)?
- The probability that both marbles selected will be blue is less than \(\frac{1}{10}\)
- Atleast 60% of the marbles in the jar are red
- Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
- Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
- BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
- EACH statement ALONE is sufficient.
- Statements (1) and (2) TOGETHER are NOT sufficient.
Answer:
Solution with Explanation
Approach Solution (1):
(1) The probability that both marbles selected will be blue is less than \(\frac{1}{10}\)
This implies that \(\frac{B}{10} * \frac{B-1}{9}<\frac{1}{10}\). So, we have that B (B – 1) < 9, thus B < 4, so the number of red marbles in the jar is 7, 8, 9, or 10
Not sufficient
(2) Atleast 60% of the marbles in the jar are red. This implies that the number of red marbles is 6 or more
Not sufficient
(1) + (2) from above, we have that R > 6
Not sufficient
Correct Option: E
Approach Solution (2):
We have 10 marbles blue and red. We need to check the probability of selecting both red marbles f is greater than 0.6
S1- We have probability of both blue is < \(\frac{1}{10}\)
So,
\(\frac{b}{10} * \frac{b-1}{9} < \frac{1}{10}\)
\(b(b-1) < \frac{90}{10}\)
\(b(b-1) < 9\)
So b can be 2, 3
If b is 2 then the probability of both red marbles is \(\frac{8}{10}*\frac{7}{9}\)which 0.622 hence greater than \(\frac{3}{5}\)but if b is 3 then the probability of both red marbles is \(\frac{7}{10}*\frac{6}{9}\)which is 0.466 so we can’t come down to a single result.
Hence not sufficient
S2: We have 60% of the marbles are red so again we have the same confusion as in S1 when the red marbles are 7 or when they are 8
So not sufficient
Combining also we do not come to any conclusion
Correct Option: E
Approach Solution (3):
We are trying to know whether there are more than 7 red balls, that is 8 or 9 red balls out of the 10 since both of these will make the possibility of two consecutive reds > \(\frac{3}{5}\). (7 reds will give us \(\frac{7}{10} * \frac{6}{9} = \frac{14}{30}\) which is < \(\frac{3}{5}\)… so we need atleast 8).
- Probability of two consecutive blues is less than \(\frac{1}{10}\)th. For this to be true; there must be either 1 blue, 2 blues, or 3 blues. Based on what we noted earlier, 1 and 2 blues will answer the target question as yes but 3 blues will make the answer no
Insufficient
- Tell us that there can be 7, 8, or 9 balls. We need to know if there are 8 greater to answer definitely
Insufficient
Combined: We can still have 1 blue and 9 reds in which case target answer is yes or 3 blues and 7 reds in which case target answer is no
Correct Option: E
“Two marbles are drawn from a jar with 10 marbles. If all marbles are either red or blue, is the probability that both marbles selected will be red greater than \(\frac{3}{5}\)?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "GMAT Quantitative Review". GMAT Quant section consists of a total of 31 questions. GMAT Data Sufficiency questions consist of a problem statement followed by two factual statements. GMAT data sufficiency comprises 15 questions which are two-fifths of the total 31 GMAT quant questions.
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