Question: w, x, y, and z are integers. If w > x > y > z > 0, is y a common divisor of w and x?
(1) \(\frac{w}{x}=z^{-1}+x^{-1}\)
(2)\( w^2-wy-2w=0\)
- Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
- Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
- BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
- EACH statement ALONE is sufficient.
- Statements (1) and (2) TOGETHER are not sufficient.
Correct Answer: (D)
Approach Solution : 1
Statement - 1 : w/x = (z^-1) + (x^-1)
w/x = (1/z) + (1/x)
To get wz = x+z, multiply both sides by xz.
Z can be rearranged and factored out to yield z(w1)=x. Given that w>x>z, then z=1 (if z>1, then x>w is the opposite of the stated condition).
To get w = x+1, insert z = 1 into z(w1)=x and rearrange.
W and x are two consecutive integers if w = x+1. Now, if two successive integers are co-prime, they only have one factor in common. (For instance, 20 and 21 are consecutive integers, so the only thing they have in common is 1). Because y>1 (from y>z>0) and w and x do not share any common factors greater than 1, y is not a common factor of w and x.
Therefore this statement is sufficient
Statement - 2 : (w^2) - wy -2w = 0
From this we can write, w(w−y−2)=0,
since w>0,
=> w−y−2=0
=> w−2=y
w>x>w−2 (Let us substitute y in the given inequality)
Therefore x = w−1.
Therefore this statement is sufficient.
Approach Solution : 2
w > x > y > z > 0 is known. Thus, z's minimum value is 1. y has a minimum value of 2.
Let us regard case 1 as having the following values, z = 1, y = 2, x = 3, and w = 4. Y is not a factor of both x and w in this situation.
And the values z = 1, y = 2, x = 4, and w = 8 in case 2. Y is a factor of both x and w in this situation.
Statement - 1 : w/x = (z^-1) + (x^-1)
Change the values in the equation (w/x) = (1/z) + (1/x) to reflect each case.
Case 1: The numbers make the equation work.
Case 2: The values are insufficient to solve the equation.
Therefore this statement is sufficient
Statement - 2 : (w^2) - wy -2w = 0
We can write this as w(w - y - 2) = 0
=> It is either w = 0 or (w - y - 2) = 0
w will not be 0 because w > 0. Thus, w - y = 2.
Change the values in the equation to reflect each case.
Case 1: The numbers make the equation work.
Case 2: The values are insufficient to solve the equation.
Therefore this statement is sufficient
Approach Solution : 3
Statement - 1 : w/x = (z^-1) + (x^-1)
We can write, w = (x/z) + 1
=> w−1 = x/z
We can arrange things like this on the number line: —-x ——- x/z---- w
Here x/z and w are two consecutive integers
Because there cannot be an integer(x) between two consecutive integers, we cannot have —-x/z—-x—-w as.
As a result, x/z>x => z<1.
This, however, is impossible because z must be at least 1. The only solution is therefore when x/z and x coincide. That is x/z = x => z=1.
Y (which is not equal to 1) can never be a divisor for both x and w because w and x are consecutive integers.
Therefore this statement is sufficient
Statement - 2 : (w^2) - wy -2w = 0
We know that w≠0 and w = y+2. Thus, on the number line, --y ---(y+1)----w.
Since y
Therefore this statement is sufficient
“w, x, y, and z are integers. If w > x > y > z > 0, is y a common” - is a topic of the GMAT Quantitative reasoning section of GMAT. GMAT Quant section consists of a total of 31 questions. GMAT Data Sufficiency questions consist of a problem statement followed by two factual statements. GMAT data sufficiency comprises 15 questions which are two-fifths of the total 31 GMAT quant questions.
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