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Question: What is the area of the triangle with the following vertices L(1,3) M(5,1) and N(3,5)?
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“What is the area of the triangle with the following vertices L(1,3) M(5,1) and N(3,5)?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "GMAT Quantitative Review". GMAT Quant section consists of a total of 31 questions. To solve GMAT Problem Solving questions a student must have knowledge about a good amount of qualitative skills. The GMAT quant topics in the problem-solving part require calculative mathematical problems that should be solved with proper mathematical knowledge.
Answer:
Approach Solution 1-
Vertices of the triangle are: L(1,3) M(5,1) and N(3,5).
Using these vertices, plot a graph as shown in the figure below:
We can see that a red triangle is formed by joining all those points. Now make a square around this triangle.
Firstly, find the area of the square formed in the figure as:
Length of the side of square = 4
Area of square = \((side)^2\)= \(4^2\)= 16
Now, we will find the area of the corner right-angled triangles formed outside the red triangle and inside the square:
Area of a triangle =\(\frac{1}{2}*B*H\)
Hence, from the figure drawn above: -
Area of Triangle (1) = \(\frac{1}{2}*B*H\)= \(\frac{1}{2}*2*2\)= 2
Area of Triangle (2) = \(\frac{1}{2}*B*H\) = \(\frac{1}{2}*2*4\) = 4
Area of Triangle (3) = \(\frac{1}{2}*B*H\)= \(\frac{1}{2}*2*4\) = 4
Hence, Total Area of Triangle = 2 + 4 + 4 = 10
Now, we will calculate the Area of Red Triangle
So, Area of Red Triangle = Area of square – Area of corner triangles
Area of Red Triangle = 16 – 10 = 6
Final Answer = 6
Correct option: D
Approach Solution 2-
In this method, we will directly use the formula to calculate the area of the triangle.
Write down the original vertices of the triangle:
\((x_1,y_1)\)= (1,3)
\((x_2,y_2)\)= (5,1)
\((x_3,y_3)\)= (3,5)
Now plot the graph using these vertices:
If the vertices of a triangle are given
Then Area of \(\bigtriangleup{LMN}\)= \(\frac{1}{2}|x_1(y_2,y_3)+x_2(y_3,y_1)+x_3(y_1,y_2)\)
Area of \(\bigtriangleup{LMN}\) = \(\frac{1}{2}| 1 (1 – 5) + 5 (5 – 3) + 3 (3 – 1)|\)
Area of \(\bigtriangleup{LMN}\)= \(\frac{1}{2}|1 (-4) + 5 (2) + 3 (2)|\)
Area of \(\bigtriangleup{LMN}\)= \(\frac{1}{2}|- 4 + 10 + 6\)|
Area of \(\bigtriangleup{LMN}\)= \(\frac{1}{2}|12|\)
Area of \(\bigtriangleup{LMN}\)= 6
Correct option: D
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