NEET 2022 Chemistry Question Paper with Solutions PDF Code R6

NEET 2022 Chemistry Question Paper with Solutions PDF Code R6 is available for download. NEET 2022 R6 Chemistry Question Paper comprises 50 MCQs out of which only 45 are to be attempted. NEET 2022 Chemistry question paper code R6 is divided into 2 sections- A (35 questions) and B (15 questions).

NEET 2022 Chemistry Question Paper with Solutions PDF Code R6

NEET 2022 Chemistry Question Paper R6 PDF NEET 2022 Chemistry Answer Key R6 PDF
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NEET Questions

  • 1.
    Minority carriers in a $p-type$ semiconductor are

      • Holes
      • Free electrons
      • Both holes and free electrons
      • Neither holes nor free electrons

    • 2.
      Penicillin was first discovered by

        • Alexander Fleming
        • Tence and Salke
        • S.A. Waksman
        • Louis Pasteur

      • 3.
        A colourless, neutral, paramagnetic oxide of Nitrogen $'P'$ on oxidation gives reddish brown gas $Q$. $Q$ on cooling gives colourless gas $R$. $R$ on reaction with P gives blue solid $S$. Identify $P , Q , R , S$, respectively

          • $N _{2} O\, NO\, NO _{2} \,N _{2} O _{5}$
          • $N _{2} O\, NO _{2}\, N _{2} O _{4} \,N _{2} O _{3}$
          • $NO \,NO _{2} \,N _{2} O _{4}\, N _{2} O _{3}$
          • $NO \,NO\, N _{2} O _{4} \,N _{2} O _{5}$

        • 4.
          A coil of inductive reactance $1/ \sqrt{3}\, O$ and resistance $1 \, \Omega$ is connected to a $200\, V$, $50\,Hz \,A.C.$ supply. The time lag between maximum voltage and current is

            • $\ce{\frac{1}{300} \,s}$
            • $\ce{\frac{1}{600} \,s}$
            • $\ce{\frac{1}{500} \,s}$
            • $\ce{\frac{1}{200} \,s}$

          • 5.
            Conjugate acid of $SO_4^{2-}$ is

              • $HSO^-_4$
              • $HSO_4$
              • $H_2SO_4$
              • $SO^{2-}_4$

            • 6.

              Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)

                • N2 + O2 → N2O5 (unbalanced equation)
                • 2N2 + 5O2 → 2N2O5
                • option 3

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