GATE 2013 Electronics and Communication Engineering (EC) Offline Question Paper with Answer Key PDF- Slot 4 (February 10- Afternoon Session)

GATE 2013 Electronics and Communication Engineering (EC) Slot 4 - Offline Question Paper with Answer Key pdf is available for download. The exam was conducted by IIT Bombay on February 10 in the Afternoon Session. In terms of difficulty level, GATE Electronics and Communication Engineering (EC) Slot 4 - Offline was of Moderate to Difficult level. The question paper comprised a total of 65 questions from General Aptitude and Electronics and Communication Engineering (EC) Slot 4 - Offline topics.

GATE 2013 Electronics and Communication Engineering (EC) Offline Question Paper with Answer Key PDF- Slot 4- Afternoon Session

GATE 2013 Electronics and Communication Engineering (EC) Question Paper PDF GATE 2013 Electronics and Communication Engineering (EC) Answer Key PDF
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GATE Questions

  • 1.

    sample text 2

      • dsfdg

      • fdgd


    • 2.

      The area of a rhombus whose vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order, is:

        • 12 sq.units

        • 24 sq.units


      • 3.
        Direction: In these tests you will find an Incomplete Figure and four Answer Figures. You have to select one diagram from the Answer Figures which fits into the blank column in Incomplete Figure in order to complete it
        Incomplete Figure

        Answer Figures

          • Figure (a)

          • Figure (b)

          • Figure ©


        • 4.
          For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

            • $\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
            • $({\frac{x^3}{9}})$
            • \(\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]\)

            • $\omega\propto\,n^{\frac{1}{3}}$

          • 5.

            test

              • test

              • test


            • 6.

              Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)

                • N2 + O2 → N2O5 (unbalanced equation)
                • 2N2 + 5O2 → 2N2O5
                • option 3

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